Write first three terms of the sequence whose nth term is defined asn^2+1
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Answer:
2, 5, 10
Step-by-step explanation:
nth term = n^2+1
1 st term( n=1) gives 1+1 = 2
substitute2 and 3 for n for getting 2 nd and 3 rd term
Answered by
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Answer:
Here, cn=6n(n+1)(2n+1),∀nϵN
For n=1,c1=61(1+1)(2(1)+1)=1.
For n=2,c2=62(2+1)(4+1)=62(3)(5)=5.
Finally n=3,c3=63(3+1)(7)=6(3)(4)(7)=14.
Hence, the first three terms of the sequence are 1,5, and 14.
In the above example, we were given a formula for the general term and were able to find any particular term directly. In the following example, we shall see another way of generating a sequence
Step-by-step explanation:
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