Question

Write five pairs of integers (a, b) such that a÷b= - 3. One such pair is (6,-2) because 6÷ (-2)= (-3)​

Answer 1

Answer:

(-3,1) (-18,6) (-27,9) (-12,4) (-30,10)

Step-by-step explanation:

Answer 2

Answer:

The pairs are;

i. (1,-1/3)

ii. (2,-2/3)

iii. (3,-1)

iv. (4,-4/3)

v. (5,-5/3)

Step-by-step explanation:

Since given condition is:

a/b = -3 --(i)

Thus, there can be infinite values of 'a' and 'b' that may satisfy the above condition.

Now to determine certain values(5 as required), we simply suppose values of 'a' randomly and put ot in the condition to determine 'b'.

For a = 1;

eq(i)=>

a/b = -3

1/b = -3

Thus,

b = -1/3.

Thus one pair obtained is (1,-1/3)

For a = 2:

eq(i)=>

a/b = -3

2/b = -3

Thus ,

b = -2/3

Thus, another pair is (2,-2/3)

For a = 3:

eq(i)=>

a/b = -3

3/b = -3

b = -1

Thus, another pair is (3,-1)

Fir a= 4:

eq(i)=>

a/b = -3

4/b = -3

b = -4/3

Thus, another pair is (4,-4/3)

For a = 5:

eq(i)=>

a/b = -3

5/b = -3

b = -5/3

Thus the last pair is (5,-5/3)