Write five pairs of negative integers (a,b)
such that a-b=8. One such pair is (-5, -13) because (-5)-(-13) = 8.
Answers
Answer:
1) (-9,-17)
2) (-1,-9)
3) (-2,-10)
4) (-3,-11)
5) (-4,-12)
Step-by-step explanation:
1) (-9)-(-17)= -9+17=8
2)(-1)-(-9)= -1+9 = 8
3)(-2)-(-10)= -2+10=8
4) (-3)-(-11)= -3+11=8
5) (-4)-(-12)= -4+12 =8
Given that condition is a - b = 8, where a and b both are integers.
Now,
First integer
(-9)-(-17)= -9+17=8, therefore, the pair is (-9,-17)
Second integer
(-1)-(-9)= -1+9 = 8, therefore, the pair is (-1,-9)
Third integer
(-2)-(-10)= -2+10=8, therefore, the pair is (-2,-10)
Fourth Integer
(-3)-(-11)= -3+11=8, therefore, the pair is (-3,-11)
Fifth integer
(-4)-(-12)= -4+12 =8, therefore, the pair is (-4,-12)
therefore, the result is
(-9,-17), (-1,-9), (-2,-10), (-3,-11), and (-4,-12).
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https://brainly.in/question/61634
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