write four solution for this3=2x+y
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2x + y = 3
=> y = 3 - 2x
First case : X = 1
=> y = 3 - 2 ( 1 )
=> y = 3 - 2 = 1
Hence x = 1, y = 1
Second case : X = 2
=> y = 3 - 2 ( 2 )
=> y = 3 - 4
=> y = ( - 1 )
Hence x = 2, y = ( - 1 )
Third case : X = 0
=> y = 3 - 2 ( 0 )
=> y = 3 - 0
=> y = 3
Hence x = 0, y = 3
Fourth case : X = ( - 1 )
=> y = 3 - 2 ( - 1 )
=> y = 3 - ( - 2 )
=> y = 3 + 2
=> y = 5
Hence x = ( - 1 ) , y = 5
These are the four solutions.
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