write four solution of an eqution 2x + y = 7
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Answered by
0
Answer:
assume that x=3
2×3+y=7
6+y=7
y=7-6
y=1
Answered by
0
Answer:
put x = 0 y = 0+7 = 7
put x = 1, 2*1 + y = 7 => y = 5
put x = 2, 2*2 + y = 7 => y = 7 - 4 = 3
put x = 3, 3*2 + y = 7 => y = 7 - 6 = 1
therefore four solutions are,
x=0 , y =7
x = 1, y = 5
x = 2 , y = 3
x = 3, y = 1
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