Write general solution of
tan²θ=tan²α
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Answer:
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Explanation:
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Explanation:
tan²θ = tan²α
tan²θ = tan²α = 0
(tanθ − + tanα)(tanθ + tanα) = 0
tanθ - tanα = 0 or tanθ + tanα = 0
tanθ = tanα or tanθ + tan(α-)
θ = nπ + α or θ = nπ - α, n ∈ I
Hence, θ = nπ ± α, n ∈ I
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