Math, asked by shubhamverma19270, 4 months ago

write half angular formulae for cos2A​

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Answered by PᴀʀᴛʜTʀɪᴘᴀᴛʜɪ
0

Answer:

If we now replace A by (1/2)A, and take the square root we get: . Similarly, we compute the sine half-angle: cos (2A) = cos2(A) − sin2(A) = 1 − sin2(A) − sin2(A) = 1 − 2sin2(A)

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