Question

Write hybridization of CH4, PCl5 and SF4.

Answer 1

Here’s a shortcut for figuring out the hybridization of an atom in a molecule. This will save you a lot of time.

Here’s what you do:

Look at the atom.

Count the number of atoms connected to it.

Count the number of lone pairs attached to it.

Add these two numbers together.

If it’s 4, your atom is sp3.

If it’s 3, your atom is sp2.

If it’s 2, your atom is sp.  

(If it’s 1, it’s probably hydrogen!)

(There’s exceptions, but you usually don’t meet them until Org 2 – if the word “aromaticity” means nothing to you as a chemistry concept, don’t worry about it for now).

Try it out here. Don’t worry if the molecule looks a little crazy: just focus on the individual atoms that the arrows point to (A, B, C, D, E). A and B especially.  If you haven’t learned line diagrams yet (and “hidden” hydrogens) maybe come back to this later.

Answer 2

$Here \: is \: the \: answer \: of \: your \: question$

`$\textbf{Hybridization}$`

= The process of mixing orbital with different energy levels and shapes of the orbitals.

`$\textbf{1. Hyberdisation of CH4}$`

Valence number of electrons in C = 4

Atoms of H = 4

Formula = ½ (V + M - C + A)

= ½ (4 + 4)

= 8/2

= 4

Hybridization = Sp³

`$\textbf{2. Hyberdisation of PCl5}$`

Valence number of electrons in P = 5

Atoms of Cl = 5

Formula applied = ½ (V + M - C + A)

= ½ (5 + 5) = 10/2

= 5

Hybridization of PCl5 = Sp³d

`$\textbf{3. Hybridization of SF4}$`

Valence electrons in S = 6

Atoms of F = 4

Formula = ½ (V + M - C + A)

= ½ (6 + 4)

= 10/2 = 5

Hyberdisation of SF4 = Sp³d

→ [Their structures are in attachment]