write in ascending order :- 6√5 , 7√3 and 8√2
Binson1:
pls show me the full solution
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squaring all the numbers
[tex] 6 \sqrt{5} ^{2} = 80 [/tex]

so,
6root5 < 8root2 < 7root3
[tex] 6 \sqrt{5} ^{2} = 80 [/tex]
so,
6root5 < 8root2 < 7root3
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