Question

Write in polar form -2i

Answer 1

Answer:

2(cos 0+ isin 0)

Step-by-step explanation:

-2i

we know that the polar form of a complex number is r(cos teete+i sin teeta)

[where r=√x^2+y^2 and teeta = tan inverse (y/x)]

-2i=0-2i

therefore x=0 and y=-2

r=√(0)^2+(-2)^2

=√0+4

=√4

=2

teeta = tan inverse (-2/0)

= tan inverse (0)

= tan inverse (tan 0)

teeta = 0

since,r(cos teeta+i sin teeta)

2(cos 0 + sin 0)

Answer 2

Answer:

Polar form is Rei thita,and since we know that eithita=cos thita+sin thita, I=eiπ2

Therefore, 2i=2eiπ2