Question

write in polar form-3√2+3√2i​

Answer 1

Answer:

z=6[cos(pi/4)+isin(pi/4)]

Step-by-step explanation:

first of all we know that the polar for of

complex number is z=|z|[cos@+sin@] so

(( I will assume that theta=@))

where |z|=r=root under x^2+ y^2

Now given is 3root3+i3root3

so, x=3root3 and y=3root3

calculate the r then we get r= 6.

then x= rcos@ and y=rsin@.

3root3=6cos@

=> cos@=3root3/6

=> cos@=1/root2

=> cos45°= 1/root2

so @= 45°

same as the sin@

calculate the value and we get the @=45°=pi/4

then put the all value

z=r[cos@+isin@]

z=6[cos45°+isin45°] it's our answer.

Answer 2

I hope this will help you!!!