Question

Write in the expanded form. (2x-y+ z)2
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Answer 1

Used identity:-

${ (a + b + c) }^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca$

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${(2x-y+ z)}^{2} = {(2x)}^{2} + {( - y)}^{2} + {(z)}^{2} + 2 \times 2x \times ( - y) + 2 \times ( - y) \times z + 2 \times z \times 2x \\ \\ = = > \: \: \: = 4 {x}^{2} + {y}^{2} + {z}^{2} - 4xy - 2yz + 4xz$

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