write iupac names of following
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Answered by
14
Hello Madam Nisha....
In your question, all the organic compounds are in their condensed form. First, break them into their structural formula.
(a) When you break this compound into its structural formula, it is clear that there are 8 Carbon atoms in the longest chain. An alcohol group is attached to the 3rd Carbon and a Methyl group is attached to the 6th carbon.
Hence, the IUPAC name of the compound is:
6-Methyl-Octan-3-ol
(b) When you break this compound into its structural formula, it is clear that there are 6 carbon atoms in total. Two Ketone groups are attached to two carbon atoms; one at the 2nd carbon and the other at the 4th.
Hence, the IUPAC name of the above compound is:
Hexane-2-4-dione
(c) When you break this compound to its structural formula, it is clear that there are 5 carbon atoms in the longest chain (including the carbon in the COOH) group, and a Bromine group is attached to the 4th carbon and carboxylic acid group is attached to the first carbon.
Hence, IUPAC name of the above compound is:
4-Bromo-Pentan-1-oic acid
HOPE MY ANSWER IS SATISFACTORY....
Thanks....(^_^)
In your question, all the organic compounds are in their condensed form. First, break them into their structural formula.
(a) When you break this compound into its structural formula, it is clear that there are 8 Carbon atoms in the longest chain. An alcohol group is attached to the 3rd Carbon and a Methyl group is attached to the 6th carbon.
Hence, the IUPAC name of the compound is:
6-Methyl-Octan-3-ol
(b) When you break this compound into its structural formula, it is clear that there are 6 carbon atoms in total. Two Ketone groups are attached to two carbon atoms; one at the 2nd carbon and the other at the 4th.
Hence, the IUPAC name of the above compound is:
Hexane-2-4-dione
(c) When you break this compound to its structural formula, it is clear that there are 5 carbon atoms in the longest chain (including the carbon in the COOH) group, and a Bromine group is attached to the 4th carbon and carboxylic acid group is attached to the first carbon.
Hence, IUPAC name of the above compound is:
4-Bromo-Pentan-1-oic acid
HOPE MY ANSWER IS SATISFACTORY....
Thanks....(^_^)
Answered by
8
hey folk....
IUPAC names are as follows:-
(a) 3-Hydroxy - 6 - methyloctane
(b) Hexan - 2,4 - dione
(c) 4 - Bromo, pentan-1-oic acid OR 4 - Bromo, pentanoic acid
Thank you
HOPE IT HELPS
IUPAC names are as follows:-
(a) 3-Hydroxy - 6 - methyloctane
(b) Hexan - 2,4 - dione
(c) 4 - Bromo, pentan-1-oic acid OR 4 - Bromo, pentanoic acid
Thank you
HOPE IT HELPS
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