Write IUPAC names of the following a. CH3-CH=CH-CH2-C=-CH
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CH3-CH=CH-CH2-CCH
If the right terminal bond you wanted to show was a triple bond then the name will be :
Hex-4-en-1-yne
Else if the last it is a double bond then the name should be:
Hexa-1,4-diene.
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Explanation:
According to lowest octet rules numbering start from alkene
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