Chemistry, asked by anasmohammad258, 11 months ago

Write lewis dot structure of Mg2+

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Answered by amikkr
0

The lewis dot structure of Mg2+ is 1s2 2s2 2p6 3s2 and Mg2+ has the configuration 1s2 2s2 2p6.

  • Lewis symbols, which represent the electrons as dots, are used in the Lewis structure.
  • Two electrons are lost from the magnesium atom, creating the magnesium ion, or Mg2+.
  • Mg has the electrical configuration 1s2 2s2 2p6 3s2 and Mg2+ has the configuration 1s2 2s2 2p6.
  • Magnesium hence gains a +2 charge upon losing the outermost two electrons. the valence electrons are eight as a result (two electrons from the s shell and six electrons from the p shell).
  • As a result, with the Lewis dot structure, eight dots are shown surrounding the Mg atom.
  • The magnesium atom's electrical configuration is 2, 8, 2. Mg2+ ion is created when the magnesium atom loses two electrons from its outermost shell.
  • Mg2+ has a total of 10 electrons as a result. Mg2ion +'s has an electrical configuration of 2, which equals eight.
  • Magnesium loses 2 electrons because it has a +2 charge in Mg 2 +. As a result, there are 12 - 2 = 10 electrons.
  • Consequently, the electronic valence shell structure of magnesium is 3 s 2.

The lewis dot structure of Mg2+ is 1s2 2s2 2p6 3s2 and Mg2+ has the configuration 1s2 2s2 2p6.

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