Question

write log 64 729 in its expansion form​

Answer 1

Answer:

(Log 3^6)Log2^6

=6 log 3/6 log 2=log 3/log 2=(log 3 base 2)

Answer 2

The expansion form is $\log\frac{64}{729}=6\log (\frac{2}{3})$.

Step-by-step explanation:

Given : Expression $\log\frac{64}{729}$ in its expansion form ?

Solution :

We can write $64=2^6$ and $729=3^6$

Write the expression as,

$\log\frac{64}{729}=\log (\frac{2^6}{3^6})$

$\log\frac{64}{729}=\log (\frac{2}{3})^6$

$\log\frac{64}{729}=6\log (\frac{2}{3})$

Therefore, the expansion form is $\log\frac{64}{729}=6\log (\frac{2}{3})$.

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Log 64/729 in its expansion form​

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