write molecular orbital configuration for the following ions. Comment on the paramagnetic properties of these ions: N2+ and N2 2- AllNewsImagesVideosMore SettingsTools
Answers
Answered by
5
Orbital configuration of N2
σ1s2, σ*1s2, σ2s2, σ*2s2, π2py2 ≈ π2pz2, σ2px2
Orbital configuration of N2 +
σ1s2, σ*1s2, σ2s2, σ*2s2, π2py2 ≈ π2pz2, σ2px1
Bond order = (no. of electrons in bonding orbitals − no. of electrons in antibonding orbitals)2
Bond order of N2 = (10−4)2 = 3
Bond order of N2 + = (9−4)2= 2.5
σ1s2, σ*1s2, σ2s2, σ*2s2, π2py2 ≈ π2pz2, σ2px2
Orbital configuration of N2 +
σ1s2, σ*1s2, σ2s2, σ*2s2, π2py2 ≈ π2pz2, σ2px1
Bond order = (no. of electrons in bonding orbitals − no. of electrons in antibonding orbitals)2
Bond order of N2 = (10−4)2 = 3
Bond order of N2 + = (9−4)2= 2.5
Similar questions