Chemistry, asked by sangipagikethan820, 1 year ago

WRITE NERNST EQUATION FOR SINGLE ELECTRODE POTENTIAL ??

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Answered by komi1897ramanujan
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Answered by Alleei
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Answer : The Nernst equation for single electrode potential is:

E_{ox}=E^o_{ox}-\frac{2.303RT}{nF}\log [M^{n+}]

Explanation :

Single electrode potential : The tendency of an electrode to lose or gains electrons when it is in contact with its own ions in solution is called electrode potential.

The general oxidation reaction is,

M\rightarrow M^{n+}+ne^-

The Nernst equation will be:

E_{ox}=E^o_{ox}-\frac{2.303RT}{nF}\log \frac{[M^{n+}]}{[M]}

The concentration of pure liquid and solid are takes as one. So, the expresion will be:

E_{ox}=E^o_{ox}-\frac{2.303RT}{nF}\log [M^{n+}]

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