Question

Write nth term of an AP sum of whose n terms is Sn.

Answer 1

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✨here is ur answer...✨☺☺↓

given...Sn=Sn✔✔

to find.....a n

since Sn=Sn...

a n.. = an....
an=a+(n-1)d✔✔

also...

S(n)-S(n-1)....

✨it depends on the number of terms...(n)...✨

hope it helps...✌✌

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Answer 2

Answer:

The nth term of the series is $a_{n} = a+(n-1)d$

Step-by-step explanation:

Given AP series whose sum of n terms is $S_{n}$. we have to write the nth term of this series.

we know that sum of n terms of AP series is

$S_{n}=\frac{n}{2}[2a+(n-1)d]$ where d is the common difference.

$a_{n} = S_{n}-S_{n-1}$

               = $\frac{n}{2}[2a+(n-1)d]-\frac{n-1}{2}[2a +((n-1)-1)d]$

               = $an+\frac{n(n-1)d}{2}-(n-1)a+\frac{(n-1)(n-2)}{2}$

               = $(n-n+1)a+(n-1)d[\frac{n}{2}-\frac{(n-2)}{2}$

               = $a+(n-1)d$

Hence, the nth term of the series is $a_{n} =a+(n-1)d$