write one zero of polynomial p(x) =2x^2+7x-4
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Answered by
21
2x^2+7x-4
2x^2+8x-1x-4
2x(x+4)-1(x+4)
(2x-1)(x+4)
x=1/2 or x=-4
2x^2+8x-1x-4
2x(x+4)-1(x+4)
(2x-1)(x+4)
x=1/2 or x=-4
Answered by
17
2x^2+7x-4
=2x^2-x+8x-4
=x(2x-1)+4(2x-1)
=(x+4)(2x-1)
So the zeroes are: -4 , 1/2
=2x^2-x+8x-4
=x(2x-1)+4(2x-1)
=(x+4)(2x-1)
So the zeroes are: -4 , 1/2
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