Question

Write one zero of the polynomial.
p(x)=2x^{2} +7x-4

Answer 1

Answer:

$2 {x}^{2} + 7x - 4 = 0 \\ = > 2 {x}^{2} + 8x - x - 4 = 0 \\ = 2x(x + 4) - 1(x + 4) = 0 \\ = > (2x - 1)(x + 4) = 0 \\ = > 2x - 1 = 0 \: \: \: or \: \: x + 4 = 0 \\ = > 2x = 1 \: \: or \: x = - 4 \\ = > x = \frac{1}{2} \: or \: x \: = - 4$