Question

Write (p+2) (p-5) in general form and write the values of a , b and c

Answer 1

Answer:

p(3+6p) = –5

3p + 6p2 + 5 = 0

6p2 + 3p + 5 = 0

So, it is of the form ax2 + bx + c = 0 where a = 6, b = 3 and c = 5.

Answer 2

Answer:

a= 1, b= -3, c=-10

Step-by-step explanation:

(p+2) (p-5)

multiply what's in second  bracket by first

p*p=p², p*(-5)= -5p, 2*p=2p, (+2) * (-5)= -10

p²-5p+2p-10=0

p²-3p-10=0

this is a quadratic eqn

from this a= 1, b= -3, c=-10㏑