Write Pythagorean triple whose one member is 14
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0
Answer:
Explanation:
Find the Pythagorean among the following sets of numbers triplets from.
(i) 3, 4, 5
(ii) 2, 4, 5
(iii) 4, 5, 6
(iv) 2, 6, 7
(v) 9, 40, 41
(vi) 4, 7, 8
ANSWER:
It is known that, if in a triplet of natural numbers, the square of the biggest number is equal to sum of the squares of the other two numbers, then the three numbers form a Pythgorean triplet.
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Let us assume 2 m=14 therefore m=7
Now m
2
+1=7
2
+1=49+1=50
And m
2
−1=7
2
−1=49−1=48
Test : 14
2
+48
2
=196+1304=2500=50
2
Hence the triplet is 14,48 and 50 Answer
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Now m
2
+1=7
2
+1=49+1=50
And m
2
−1=7
2
−1=49−1=48
Test : 14
2
+48
2
=196+1304=2500=50
2
Hence the triplet is 14,48 and 50 Answer
Hope this helps you guys
Plz mark my answer as brainiest
Follow me
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