125 small liquids drops each carrying a charge of 0.5uc and each diameter 0.1 m form a bigger drop calculate the potential at bigger drop
Answers
Let r and R radii of small and bigger drop respectively.
Volume of bigger drop =1.25× volume of small drop
43πr3=125×43πr3
R=5r=5×2×10−3=10×10−3m
Capacitance fo bigger drop
C=4π∈0R=10×10−39×109=1.1pF
Charge on bigger drop, q=125×10−9C
∴ Potential of bigger drop
V=qC=125×10−91.1×10−12=113.6V
Answer:
k
Explanation:
Let Q be the charge on each drop
⇒ Voltage on each drop: V=
r
KQ
We know: C=
V
Q
or, C=
KQ
Qr
or, C=
k
r
Equating the sum of volume of drops to the volume of bigger drop:
64×
3
4
πr
3
=
3
4
πR
3
So, radius of final drop: R=(64)
3
1
r=4r
∴C
′
=
K
R
=
9×10
9
4×2×10
−2
=
9
8
×10
−11
FLet Q be the charge on each drop
⇒ Voltage on each drop: V=
r
KQ
We know: C=
V
Q
or, C=
KQ
Qr
or, C=
k
r
Equating the sum of volume of drops to the volume of bigger drop:
64×
3
4
πr
3
=
3
4
πR
3
So, radius of final drop: R=(64)
3
1
r=4r
∴C
′
=
K
R
=
9×10
9
4×2×10
−2
=9
8
×10
−11
F