write Pythagorean triplet whose leat no. 18
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Answered by
2
using general form 2m, m^2-1,m^2+1 (m^2 indicate square root)
let 2m =18
m=18÷2=9
m=9
now m^2-1=9^2-1 (9×9)
81-1 =80
m^2+1 =9^2+1
=81+1=82
so 18,80,82 are Pythagorean triplet
let 2m =18
m=18÷2=9
m=9
now m^2-1=9^2-1 (9×9)
81-1 =80
m^2+1 =9^2+1
=81+1=82
so 18,80,82 are Pythagorean triplet
Answered by
2
let us take 18 =2m and then it answer m=9 .so value of m=9 then solve 2m ;m^2-1 and m^2+1 so it will answer 18,80 and 82 which are the members of pythagoren triplet
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