Question

write quadratic equation whose roots are 1/root2 1/root 2​

Answer 1

Answer:

Step-by-step explanation:

Given that the zeros of the equation are 1/√2 and 1/√2.

Here we find that the equation has equal and identical zeros, which means that the value of the discriminant is 0.

Therefore,

Let the equation be ⇒ ax² - bx + c = 0

∴ b² - 4ac = 0

Now sum of zeros = 1/√2 + 1/√2 = -b/a

                               = 2/√2 = -b/a

                               = 2√2/2 = -b/a

Product of zeros = 1/√2 x 1/√2 = c/a

                            = 1/2 = c/a

Here we come to know that a = 2 ; b = -2√2 and c = 1

Hence, the equation becomes = 2x² - 2√2x + 1

Hope it helps you.....