Question

write root 99 + root 44 in the form A root B where A and B are integers

Answer 1

Answer:

$5\sqrt11$

Step-by-step explanation:

$\sqrt{99}$ is just $\sqrt{9*11}$ which can be rewritten as $3\sqrt{11}$ (because $9$ is $3^2$)

$\sqrt{44}$ can be rewritten as $2\sqrt{11}$ in a similar fashion.

Therefore $2\sqrt{11} + 3\sqrt{11}$ is $5\sqrt11$.

Answer 2

SOLUTION

TO DETERMINE

Write √99 + √44 in the form A√B where A and B are integers

EVALUATION

Here the given expression is

$\sf \sqrt{99} + \sqrt{44}$

We simplify it as below

$\sf \sqrt{99} + \sqrt{44}$

$\sf = \sqrt{3 \times 3 \times 11} + \sqrt{2 \times 2 \times 11}$

$\sf = \sqrt{ {3}^{2} \times 11} + \sqrt{ {2}^{2} \times 11}$

$\sf = 3 \sqrt{ 11} +2 \sqrt{ 11}$

$\sf = 5 \sqrt{ 11}$

Which is of the form A√B

where A = 5 and B = 11

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