Question

Write sample space for the event when three coins are tossed simultaneously .Find the probability of the event of getting at least one head​

Answer 1

Answer:

7/8

Step-by-step explanation:

n(E3) = 3. Therefore, P(getting 1 head) = P(E3) = n(E3)/n(S) = 3/8. and, therefore, n(E4) = 7. Therefore, P(getting at least 1 head) = P(E4) = n(E4)/n(S) = 7/8.

Answer 2

Step-by-step explanation:

7477"'*,('('+_+'+"6"6#$+8'7'_(('!"(3$8'