Question

Write secA in terms of tanA

Answer 1

Step-by-step explanation:

$we \: know \: that \: 1 + {tan}^{2}a \: = \: {sec}^{2} a \\ \\ then \: {tan}^{2}a \: = {sec}^{2} a - 1 \\ \\ tan(a) \: = \sqrt{ {sec}^{2}a - 1 }$

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Answer 2

SOLUTION:-

Given:

secA in terms of tanA

Explanation:

We know that, 1+tan²A=sec²A

⇒tan²A=sec²A-1

⇒tanA=√sec²A-1

Here, A is a acute angle.