write so
[y +z] -5 [+ 2) as factors
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HI MATE ...... :)
Step-by-step explanation:
Let us first manipulate the first term.
x(y−z)3=x(y−z){(y+z)2–4yz} Now replace y+z by −x
=x(y−z){(−x)2–4yz}
=x3(y−z)−4xyz(y−z) Now replace only one x in first term by −(y+z)
=−x2(y+z)(y−z)−4xyz(y−z)
=−x2(y2−z2)−4xyz(y−z)
=x2z2−x2y2−4xyz(y−z)…………………(1)
Similarly
y(z−x)3=y2x2−y2z2−4xyz(z−x)……………(2)
z(x−y)3=z2y2−z2x2−4xyz(x−y)………….(3)
Adding (1),(2) and (3)
x(y−z)3+y(z−x)3+z(x−y)3=x2z2−x2y2+y2x2−y2z2+z2y2−z2x2−4xyz(y−z+z−x+x−y)=0
PLZ MARK IT AS BRAINLIST ANSWER... :)
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Answer:
I have don't answer of your question sorry
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