Math, asked by Anonymous, 1 year ago

Write solutions of qn. no 8to21,please.

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Answered by sweta25sahu
0
19) (sin(90-43)/cos 43)^2 + (cos(90-47)/sin 47)^2 - 2*1/2
= (cos 43/cos 43)^2. + (sin 47/sin47)^2 - 1
= 1+1-1
= 1


20) cos(90-13) sin13 + sin(90-13) cos 13
= sin 13 *sin 13 + cos 13 * cos 13
= sin^2 13 + cos^2 13
= 1

21) 3 sin(90-18)/cos18 - sec(90-58)/cosec32
= 3 (cos 18/ cos18) - (cosec32/cosec32)
= 3-1=2


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