Math, asked by prachidave340, 18 hours ago

(write steps of constructions) 23) Find the smallest square number that is divisible by each of the following numbers. 8, 15, 20​

Answers

Answered by navjeetkaur89
1

Answer:

3600

Step-by-step explanation:

L.C.M. of 8, 15 and 20 is 120.

Prime factors of 120 = 2 x 2 x 2 x 3 x 5

Here, prime factors 2, 3 and 5 have no pair. Therefore 120 must be multiplied by 2 x 3 x 5 to make it a perfect square.

\therefore120\times2\times3\times5=3600∴120×2×3×5=3600

Hence, the smallest square number which is divisible by 8, 15 and 20 is 3600.

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