Question

Write the additive inverse 19/-6​

Answer 1

Answer:

The additive inverse of 19/-6 is 19/6.

Solution:

We know that the sum of a number and its additive inverse is 0.

Let the additive inverse of 19/-6 be x, so that,

x + 19/-6 = 0

And we remember that in any fraction, if either numerator only or denominator only is negative, then the fraction is also negative. But if both are simultaneously negative, then the fraction is positive.

So, here, we can write 19/-6 as - 19/6.

\dfrac{19}{-6}\ =\ \dfrac{-19}{6}\ =\ -\dfrac{19}{6}

−6

19

=

6

−19

= −

6

19

Thus,

x + (- 19/6) = x - 19/6 = 0

This implies,

x = 19/6

Or we can do it in another way.

Consider what we considered earlier!

x + 19/-6 = 0

We can equalize the denominator of all the terms, can't we?

Here the denominator of one term is -6, so let others have denominator the same.

-6x/-6 + 19/-6 = 0/-6

Subtract 19/-6 from both sides.

-6x/-6 = 0/-6 - 19/-6

⇒ -6x/-6 = (0 - 19)/-6

⇒ -6x/-6 = -19/-6

Now we can simplify both sides. Divide the numerator and the denominator of the fraction at LHS by -6 and those of fraction at RHS by -1. Thus we get,

x = 19/6.

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Answer 2

Answer:

-19/6

Step-by-step explanation:

19/6+-19/6=0

so, the additive inverse of 19/6 is -19/6

hope it helps u