Question

write the additive inverse (negative) of (a) 0 (b)-4/5 (c) 17/5​

Answer 1

Answer:

We know that additive inverse of a rational number a/b is (-a/b) such that a/b + (-a/b) = 0

(i) Additive inverse of 2/8 = -2/8

(ii) Additive inverse of -5/9 = 5/9

(iii) -6/-5 = 6/5

Additive inverse of 6/5 = -6/5

(iv) 2/-9 = -2/9

Additive inverse of -2/9 = 2/9

(v) 19/-6 = -19/6

Additive inverse of -19/6 = 19/6

Step-by-step explanation:

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Answer 2

Answer:

Additive inverse of a number which when added to the number itself gives zero.

(a) 0 = 0 (0+0=0)

(b) -4/5 = 4/5 (-4/5+4/5=0)

(c) 17/5 = -17/5 {17/5 + (-17/5)=0}

Hope it helps you.