Question

Write the additive inverse of 2/-9

Answer 1

Answer:

Hi Here is your answer

Step-by-step explanation:

2/-9

Answer 2

Answer:

The additive inverse of 2/-9 is $\frac{2}{9}$

Step-by-step explanation:

Here given number is $\frac{2}{ - 9}$

Here we want to find additive inverse of the given number.

We know,

If x is a number then additive inverse of x is (-x).

We can write $x + ( - x) = 0$

For example, additive inverse of 5 is (-5)

Here given number is $( - \frac{2}{9} )$

So additive inverse of the given number is $- ( - \frac{2}{9} ) = \frac{2}{9}$

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

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