write the angle of which is 1/5of its complements
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let one angle be x
another angle=1/5*x
ATQ
X+1x/5=90
5x/5+x/5=90
6x/5=90
6x=90×5
x=90÷6×5
x=75
1x/5=75/5
1x/5=15
another angle=1/5*x
ATQ
X+1x/5=90
5x/5+x/5=90
6x/5=90
6x=90×5
x=90÷6×5
x=75
1x/5=75/5
1x/5=15
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