write the angle that is one fifth of its compliment
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Answered by
5
Let the angle be x.
Therefore it's complement=(90-x)
Now, according to the question,
x=1/5(90-x)
or x=18-x/5
or x+x/5=18
or 6x/5=18
or 6x=90
Therefore, x=15
Hence the measure of the required angle is 15.
Therefore it's complement=(90-x)
Now, according to the question,
x=1/5(90-x)
or x=18-x/5
or x+x/5=18
or 6x/5=18
or 6x=90
Therefore, x=15
Hence the measure of the required angle is 15.
Answered by
2
let me take the angle equals to x 5x=90=90/5=18
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