Write the angle which is one fifth of its complement
Answers
Answered by
23
Let the angle be x.
Therefore it's complement=(90-x)
Now, according to the question,
x=1/5(90-x)
or x=18-x/5
or x+x/5=18
or 6x/5=18
or 6x=90
Therefore, x=15
Hence the measure of the required angle is 15.
Therefore it's complement=(90-x)
Now, according to the question,
x=1/5(90-x)
or x=18-x/5
or x+x/5=18
or 6x/5=18
or 6x=90
Therefore, x=15
Hence the measure of the required angle is 15.
Brainly1119:
oh solve kr diya mera bhi ques solve kro
cos2 θ = 1 − sin2 θ
tan2 θ + 1 = sec2 θ
tan2 θ = sec2 θ − 1
cot2 θ + 1 = csc2 θ
cot2 θ = csc2 θ − 1
Answered by
27
Answer:
Angle is 15°.
Step-by-step explanation:
Let x be the the complement angle.
Angle =
According to the Question,
Angles =
Therefore, Required Angle is 15°
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