Math, asked by gkrathourgaurav, 1 year ago

Write the angle which is one fifth of its complement

Answers

Answered by LavanyaN1
23
Let the angle be x. 
Therefore it's complement=(90-x) 
Now, according to the question, 
x=1/5(90-x) 
or x=18-x/5 
or x+x/5=18 
or 6x/5=18 
or 6x=90 
Therefore, x=15 
Hence the measure of the required angle is 15.

Brainly1119: oh solve kr diya mera bhi ques solve kro
LavanyaN1: what is ur question
Brainly1119: trignometric identies ka h
LavanyaN1: sin2 θ = 1 − cos2 θ
cos2 θ = 1 − sin2 θ
tan2 θ + 1 = sec2 θ
tan2 θ = sec2 θ − 1
cot2 θ + 1 = csc2 θ
cot2 θ = csc2 θ − 1
Answered by aquialaska
27

Answer:

Angle is 15°.

Step-by-step explanation:

Let x be the the complement angle.

Angle = \frac{1}{5}\times x

According to the Question,

x+\frac{1}{5}\times x=90

x+\frac{x}{5}=90

\frac{5x+x}{5}=90

6x=90\times5

6x=450

6x=450

x=\frac{450}{6}

x=75

Angles = \frac{75}{x}=15^{\circ}

Therefore, Required Angle is 15°

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