Question

Write the arithmetic aequance with first term 10 and common difference 4? b) Write the difference of the terms in the same position of the above sequance and the arithmetic sequance 11, 17, 23........

Answer 1

First term of the sequence is 10 and common difference is 3.

a

1

= 10 and d = 3

Next term = a

2

=a

1

+d=10+3=13

a

3

=a

2

+d=13+3=16

Thus, first three terms of the sequence are 10, 13 and 16.

Let 100 be the nth term of the sequence.

a

n

=a

1

+(n−1)d

100=10+(n−1)3

90=(n−1)3

n−1=30

n=31, which is a whole number.

Therefore, 100 is the 31

st

term of the sequence.