write the arithmetic sequence with first term 8 and common difference 3.check whether 100 is a term in the sequence.check whether the difference of any two terms of this sequence will be 2017.find the position of the term 125 in the sequence.
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Step-by-step explanation:
First term of the sequence is 10 and common difference is 3.
a1 = 10 and d = 3
Next term = a2=a1+d=10+3=13
a3=a2+d=13+3=16
Thus, first three terms of the sequence are 10, 13 and 16.
Let 100 be the nth term of the sequence.
an=a1+(n−1)d
100=10+(n−1)3
90=(n−1)3
n−1=30
n=31, which is a whole number.
Therefore, 100 is the 31st term of the sequence.
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