Question

Write the atomicity of phosphorus, neon, chlorine, selenium, sulphur, oxygen and boron ?











.

Answer 1

Here is Ur answer,

Atomicity of.......
Phosphorus - 4
neon - 1
chlorine - 2
selenium - don't know
sulphur - 8
oxygen - 3
boron - +3

Hope it helps u......

Answer 2

Answer:

Atomicity is defined as the number of atoms present in a molecule or it can be calculated by dividing the atomic weight of an element to its atomic number.

Atomicity= atomic mass / atomic number

Explanation:

Atomicity of Phosphorus (P) is 4, as it is present in tetravalent form. And its atomic number is 15 and atomic mass number is 30. Therefore, it's atomicity is 30/15 = 2.

Atomicity of Neon (Ne) is 1, as Neon is a noble gas therefore it is a very stable substance and thus it has only one atom in its molecule.

Atomicity of Chlorine is 2 as chlorine present in a diatomic form in the nature. And its atomic mass number is 35.5 and atomic number is 17. Therefore, atomicity of chlorine is 35.5 / 17 = 2.08

Atomicity of Selenium (Se) is 2 as its mass number is 78 and atomic number is 34. Hence, it's atomicity is 78/34 = 2.

Sulphur exists in a polyatomic form in the nature and its compound has 8 atoms, therefore its atomicity is 8.

Oxygen is a diatomic gas as its molecule has only two 2 atoms. Therefore, its atomicity is 2.

Boron is an allotropic element, although its atomicity is 1 as it is present in monoatomic form.

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