Write the balanced chemical equations for the following reaction and identify the type in each case:
1) Nitrogen gas is treated with hydrogen gas in the presence of a catalyst at 773K to form ammonia gas
2) Sodium hydroxide solution is treated with acetic acid to form sodium acetate and water.
3) Ethanol is warmed with ethanoic acid to form ethyl acetate in the presence of concentrated H2SO4.
4) Ethene is burnt in the presence of oxygen to form carbon dioxide, water and releases heat and light.
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7
Answer:
1) Nitrogen gas is treated with hydrogen gas in the presence of a catalyst at 773K to form ammonia gas.
Answer: N2 + 3H2 + Catalyst/773 K ⇨ 2NH3
2) Sodium hydroxide solution is treated with acetic acid to form sodium acetate and water.
Answer: NaOH + CH3COOH ⇨ CH3COONa + H2O
3) Ethanol is warmed with ethanoic acid to form ethyl acetate in the presence of concentrated H2SO4 .
Answer: C2H5OH + CH3COOH ⇨ CH3COOC2H5 + H2O
4) Ethene is burnt in the presence of oxygen to form carbon dioxide, water and releases heat and light.
Answer: C2H4 + 3O2 ⇨ 2CO2 + 2H2O + Heat + Light
(a) and (c) are combination reactions, (b) is double displacement reaction and (d) is redox reaction.
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2
Answer:
1. N2+ 3H2 ----> 2NH3
2. NaOH + CH3COOH ------> CH3COONa +H2O
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