Write the balanced equation with state of symbols
1 Lead nitrate solution react with potassium iodide solution and foolish yellow precipitate of lead iodide and a solution of potassium nitrate solution
Answers
Answered by
5
Answer:
Pb(NO3)2(aq)+2KI(aq)=2KNO3(aq)+PbI2(s)
yellow ppt
Answered by
3
Answer:
Pb(NO3)2 + Kl ↪Pbl + KNO3
Explanation:
the reactant lead nitrate and potassium iodide is colourless when the product form lead nitrate is in yellow colour
It means the observation which help to identify in this formula is CHANGE IN COLOUR
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