Write the chemical equation for obtanng rthyl alcohol from sucrose
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Explanation:
This is a reduction-oxidation reaction.
You can find the general technique for balancing redox equations here.
We can use the method of oxidation numbers to balance this equation.
We start with the unbalanced equation:
C12H22O11+H2O→C2H5OH+CO2
Step 1. Identify the atoms that change oxidation number
Determine the oxidation numbers of every atom in the equation.
0C12+1H22-2O11+l+1H2-2O→-2C2+1H5-2O+1H++4C-2O2
0C12+22H22-22O11++2H2-2O→-4C2+5H5-2O+1H++4C-4O2
We see that the oxidation number of C in sucrose is reduced to -2 in C2H5OH and increased to +4 in CO2.
This is a disproportionation reaction.
The changes in oxidation number are:
C: 0 → -2;lChange =m-2 (oxidation)
C: 0 → +4;Change =l+4 (reduction)
Step 2. Equalize the changes in oxidation number
We need 2 atoms of C that become ethanol for every 1 atom of C that becomes CO2.
We must also have a total of 12 C atoms from the sucrose.
That means we need 1 molecule of sucrose, 4 of ethanol, and 4 of CO2.
Step 3. Insert coefficients to get these numbers
1C12H22O11+H2O→4C2H5OH+4CO2
Step 4. Balance O
We have fixed 12 O atoms on the right and 11 Oatoms on the right, so we need 1 more O atoms on the left. Put a 1 before H2O.
1C12H22O11+1H2O→4C2H5OH+4CO2
Every formula now has a coefficient. The equation should be balanced.
Step 5. Check that all atoms are balanced.
On the leftlOn the right
mm12 Cmmmml12 C
mm24 Hmmmml24 H
mm12 Ommmml12 O
The balanced equation is
C12H22O11+H2O→4C2H5OH+4CO2
This is a reduction-oxidation reaction.
You can find the general technique for balancing redox equations here.
We can use the method of oxidation numbers to balance this equation.
We start with the unbalanced equation:
C12H22O11+H2O→C2H5OH+CO2
Step 1. Identify the atoms that change oxidation number
Determine the oxidation numbers of every atom in the equation.
0C12+1H22-2O11+l+1H2-2O→-2C2+1H5-2O+1H++4C-2O2
0C12+22H22-22O11++2H2-2O→-4C2+5H5-2O+1H++4C-4O2
We see that the oxidation number of C in sucrose is reduced to -2 in C2H5OH and increased to +4 in CO2.
This is a disproportionation reaction.
The changes in oxidation number are:
C: 0 → -2;lChange =m-2 (oxidation)
C: 0 → +4;Change =l+4 (reduction)
Step 2. Equalize the changes in oxidation number
We need 2 atoms of C that become ethanol for every 1 atom of C that becomes CO2.
We must also have a total of 12 C atoms from the sucrose.
That means we need 1 molecule of sucrose, 4 of ethanol, and 4 of CO2.
Step 3. Insert coefficients to get these numbers
1C12H22O11+H2O→4C2H5OH+4CO2
Step 4. Balance O
We have fixed 12 O atoms on the right and 11 Oatoms on the right, so we need 1 more O atoms on the left. Put a 1 before H2O.
1C12H22O11+1H2O→4C2H5OH+4CO2
Every formula now has a coefficient. The equation should be balanced.
Step 5. Check that all atoms are balanced.
On the leftlOn the right
mm12 Cmmmml12 C
mm24 Hmmmml24 H
mm12 Ommmml12 O
The balanced equation is
C12H22O11+H2O→4C2H5OH+4CO2
Answered by
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The balanced equation is
The balanced equation is
C
12
H
22
O
11
+
H
2
O
→
4C
2
H
5
OH
+
4CO
2
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