write the chemical equation of the reaction with example each in which the following changes have taken place: (i) change in colour (ii)change in temperature (iii) formation of precipitation
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(i) Change in colour: Reaction between lead nitrate solution and potassium iodide solution. In this reaction, colour changes from colourless to yellow. (ii)Change in temperature: Action of dilute sulphuric acid on zinc. (iii) Formation of precipitate: Action of barium chloride on sodium sulphate
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(i)Cu (s) + 2AgNO3 (aq)———–> Cu(NO3)2(aq) + 2Ag
The solution will become blue in colour and shiny silver metal will be deposited.
(ii) NaOH + HCl ———–> NaCl + H2O+ heat
The temperature will increase because heat will be evolved.
(iii) Pb(NO3)2 (aq) + 2KI (aq)———–> Pbl2 (s) + 2KNO3 (aq)
Yellow ppt
Yellow precipitate of Pbl2will be formed.
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