Question

write the condition in terms of ∆H and∆S when a reaction would be always spontaneous

Answer 1

ΔG=ΔH-TΔS ...... thus for a reaction to be spontaneous the value of ΔG must be -ve..... now let's focus on the equation ..... ΔG is directly proportional to ΔH so ΔH must also be -ve.....moreover there is a -ve sign before TΔS thus the sign of ΔS must be +ve,...