write the condition satisfied by 455,so that 64/455 has non-terminating repeating decimal expansion
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64/455
Factorize the denominator we get
455 =5 x 7 x 13
There are 7 and 13 also in denominator so denominator is not in form of 2n×5m . hence 64/455 is not terminating.
Factorize the denominator we get
455 =5 x 7 x 13
There are 7 and 13 also in denominator so denominator is not in form of 2n×5m . hence 64/455 is not terminating.
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