Math, asked by Anonymous, 1 year ago

write the condition satisfied by 455,so that 64/455 has non-terminating repeating decimal expansion

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Answered by Nitansha
58
64/455     
      Factorize the denominator we get
                        455     =5 x 7 x 13 
       There are 7 and 13 also in denominator so denominator is not in form of 2n×5m .  hence  64/455 is not terminating.
Answered by sandon01
10

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