Question

Write the cubes of 4 natural numbers which are multiples of 3 and verify that the cube of a
natural number which is a multiple of 3 is a multiple of 27".​

Answer 1

Answer:

consider y is a multiple of 3

so y=3x(x is a natural number)

now

{y}^{3} = (3x) {}^{3} = {3}^{3} {x}^{3} = 27 {x}^{3}

which is multiple of 27

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Answer 2

I will give you answer afterwards.

Ok