Write the dimension of a/b in the relation P = (a-t)/BX
Where P is pressure, x is distance and t is time.
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➨ a & b are constants
➨ P = (a-t)/bx
➨ Px = a-t / b
➨ Px = a/b - t/b
➨ Px + t/b = a/b
Since b is constant neglecting from L.H.S
➨ Px + t = a/b
Now , P has dimensions [M L^0 T^-2] & x has [L] & t has [T]
➨ [ M L T^-1 ] = [a/b]
➨ P = (a-t)/bx
➨ Px = a-t / b
➨ Px = a/b - t/b
➨ Px + t/b = a/b
Since b is constant neglecting from L.H.S
➨ Px + t = a/b
Now , P has dimensions [M L^0 T^-2] & x has [L] & t has [T]
➨ [ M L T^-1 ] = [a/b]
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