Question

Write the dimensions of a& b for E=b-x×x ÷a×t where E is energy x is distance and t is time

Answer 1

According to the principle of homogeneity kf dimensions
Now dimension of b = dimension of x²
[b] = [L²]

For constant 'a'
The above is rearrange as. E= (b- x²)/ (at)

a= (b-x²)/(Et)
Now in dimension
[a] = [(b -x²)/(Et)]
= [L²]/[ML²T^(-2)]* [T]
=1/ [ML°T^(-1)]. ( ° is zero)
[a] = [M^(-1) L° T]

These are the required dimension of constant'a'and 'b'.
Solution by MOHAMMAD M. H. RAZA